Question

    I. 8x² + 2x – 3 = 0 II. 6y² + 11y + 4 =

    0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
    A if x > y Correct Answer Incorrect Answer
    B if x ≥ y Correct Answer Incorrect Answer
    C if x < y Correct Answer Incorrect Answer
    D if x ≤ y Correct Answer Incorrect Answer
    E if x=y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 8x² + 2x – 3 = 0 8x² + 6x - 4x – 3 = 0  2 x (4 x + 3) – 1(4 x + 3) = 0 (2x – 1) (4x + 3) = 0 x = 1/2, -3/4 II. 6y² + 11y + 4 = 0 6y² + 8y + 3y + 4 = 0 2 y(3 y + 4) + 1(3 y + 4) = 0 (2 y + 1) (3 y + 4) = 0 y = - 1/2, -4/3 Hence, no relationship can be established between x and y

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