Question
Solve: 3xΒ² β 7x β 6 = 0
Solution
3xΒ² β 7x β 6 = 0 Product = 3 Γ (β6) = β18; need two numbers with sum β7 and product β18 β β9 and 2. 3xΒ² β 9x + 2x β 6 = 0 3x(x β 3) + 2(x β 3) = 0 (3x + 2)(x β 3) = 0 So x = β2/3 or x = 3
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