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    Question

    Solve: 3xΒ² βˆ’ 7x βˆ’ 6 = 0

    A x = -3 or x = 5 Correct Answer Incorrect Answer
    B x = βˆ’2/3 or x = 3 Correct Answer Incorrect Answer
    C x = βˆ’2/5 or x = 3/5 Correct Answer Incorrect Answer
    D x = βˆ’1/3 or x = 2.5 Correct Answer Incorrect Answer

    Solution

    3xΒ² βˆ’ 7x βˆ’ 6 = 0 Product = 3 Γ— (βˆ’6) = βˆ’18; need two numbers with sum βˆ’7 and product βˆ’18 β†’ βˆ’9 and 2. 3xΒ² βˆ’ 9x + 2x βˆ’ 6 = 0 3x(x βˆ’ 3) + 2(x βˆ’ 3) = 0 (3x + 2)(x βˆ’ 3) = 0 So x = βˆ’2/3 or x = 3

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