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Question

In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer:

I. x² + 4x + 4 = 0

II. y² - 8y + 16 = 0

A if x > y Correct Answer Incorrect Answer
B if x < y Correct Answer Incorrect Answer
C if x ≥ y Correct Answer Incorrect Answer
D if x ≤ y Correct Answer Incorrect Answer
E if x=y or the relationship cannot be established. Correct Answer Incorrect Answer

Solution

I. x² + 4x + 4 = 0 Pairs are: 2, 2 So by changing its signs & dividing by a i.e.1, we will get x = -2, -2 II. y² - 8y + 16 = 0 Pairs are: -4, -4 So by changing its signs & dividing by a i.e.1, we will get y = 4, 4 Hence, x < y.

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