Question
I. x² + 4x + 4 = 0 II. y² - 8y + 16 =
0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer:Solution
I. x² + 4x + 4 = 0 Pairs are: 2, 2 So by changing its signs & dividing by a i.e.1, we will get x = -2, -2 II. y² - 8y + 16 = 0 Pairs are: -4, -4 So by changing its signs & dividing by a i.e.1, we will get y = 4, 4 Hence, x < y.
43 ? 45 39 47 37
...(45)2 ÷ ∛729 + (35)2 ÷ 1.4 =?
31     35      60     124      ?      441
...3 5 7 25 85 481
...398Â Â Â 308Â Â Â 228Â Â Â 158Â Â Â 98Â Â Â ?
16     17      25      ?     99    180
...13Â Â Â Â Â Â Â Â Â Â 182Â Â Â Â Â Â Â Â 303Â Â Â Â Â Â Â Â 384Â Â Â Â Â Â Â Â 433Â Â Â Â Â Â Â Â ?
...130   136   148   166    ?    232
124    174    211    ?     254    264
...1335Â Â Â Â Â Â 737Â Â Â Â Â Â Â Â 355Â Â Â Â Â Â Â Â 141Â Â Â Â Â Â Â Â 47Â Â Â Â Â Â Â Â Â Â ?
...
