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    Question

    I. x² + 4x + 4 = 0 II. y² - 8y + 16 =

    0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer:
    A if x > y Correct Answer Incorrect Answer
    B if x < y Correct Answer Incorrect Answer
    C if x ≥ y Correct Answer Incorrect Answer
    D if x ≤ y Correct Answer Incorrect Answer
    E if x=y or the relationship cannot be established. Correct Answer Incorrect Answer

    Solution

    I. x² + 4x + 4 = 0 Pairs are: 2, 2 So by changing its signs & dividing by a i.e.1, we will get x = -2, -2  II. y² - 8y + 16 = 0 Pairs are: -4, -4 So by changing its signs & dividing by a i.e.1, we will get y = 4, 4 Hence, x < y.

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