Question
Average speed of βAβ during a 24-hour journey is 36
km/h. If he covered the first 150 km of his journey at a speed of 15 km/h, then find the speed at which βAβ travelled during the remaining journey.Solution
Total distance covered by βAβ = 24 Γ 36 = 864 km Time taken to cover 150 km = 150/15 = 10 hours Time taken to cover remaining distance = 24 β 10 = 14 hours So, required speed = {(864 β 150)/14} = 51 km/h
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I. MASTER is written as NZHGVI
II. BOTTLE is written as YLGGOV
Statements: G ≤ H, H ≤ J, L < G
Conclusions: I. L < H II. J > L
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