Question
βIβ and βJβ started moving towards each other at
the same time with a speed of 35 km/hr and 25 km/hr, respectively. If the distance covered by βIβ is 25 km more than that by βJβ, when they meet, then find the initial distance between them.Solution
ATQ, Ratio of distance travelled by βIβ and βJβ = 35:25 = 7:5 Required distance = 25 Γ 12 = 300 km
I. xΒ² Β β 44x + 468 = 0
II. yΒ² Β β 30y + 216 = 0
I. 12 x ² - 3 x – 15 = 0
II. 2 y² + 12
I. 2x2 + 12x + 18 = 0
II. 3y2 + 13y + 12 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: xΒ² - 41x + 400 = 0
Equation 2: yΒ² - 41y + 420 = 0
I. x= Β β(20+ β(20+ β(20+ β(20β¦β¦β¦β¦β¦.β)) ) )Β
II. y= β(5β(5β(5β(5β¦β¦β¦.β)) ) )Β
...Quantity I: A vessel contains a mixture of milk and water in the ratio of 7 : 5. If 9 litre of mixture is sold and replaced by same amount of water then...
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
I. 3 x² - 10