Question
I. 2x2 - 9 x + 9 = 0 II.
2y2 - 7 y + 3 = 0Solution
I. 2x2 - 9 x + 9 = 0 2x2 - 3x - 6x + 9 = 0 x (2 x – 3) – 3(2 x – 3) = 0 (x – 3) (2x – 3) = 0 x = 3, 3/2 II. 2y2 - 7 y + 3 = 0 2y2 - y-6y + 3 = 0 y (2y – 1) – 3 (2y – 1) = 0 y = 3, 1/2 Hence, Quantity I ≥ Quantity II
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