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    Question

    I. 8x² + 2x – 3 = 0 II. 6y² + 11y

    + 4 = 0
    A if x > y Correct Answer Incorrect Answer
    B if x ≥ y Correct Answer Incorrect Answer
    C if x < y Correct Answer Incorrect Answer
    D if x ≤ y Correct Answer Incorrect Answer
    E if x=y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. 8x² + 2x – 3 = 0 8x² + 6x - 4x – 3 = 0 2x (4x + 3) – 1(4x + 3) = 0 (2x – 1) (4x + 3) = 0 x = 1/2, -3/4 II. 6y² + 11y + 4 = 0 6y² + 8y + 3y + 4 = 0 2y(3y + 4) + 1(3y + 4) = 0 (2y + 1) (3y + 4) = 0 y = - 1/2, -4/3 Hence, no relationship can be established between x and y

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