Question
A group consists of 9 boys and 8 girls. In how many ways
can 3 boys and 5 girls be selected from the group?Solution
Required number of ways = 9 C 3 × 8 C 5
= (9! / (3! × 6!)) × (8! / (5! × 3!))
= 84 × 56 = 4,704
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