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    Question

    How many numbers of five digits may be formed with the

    digits 5, 0, 9, 0, and 6?
    A 44 Correct Answer Incorrect Answer
    B 36 Correct Answer Incorrect Answer
    C 30 Correct Answer Incorrect Answer
    D 42 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ³P1 ways and remaining 4 digits 4!/2! (as 0 occurs twice) ways ³P1 × 4!/2! = (3×4×3×2!)/2! = 36 ways

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