Question
I. 2x² - 9x + 10 = 0 II. 3y² + 11y + 6
= 0Solution
I. 2x² - 9x + 10 = 0 2x² - 5x - 4 x + 10 = 0 x (2 x – 5) – 2(2 x – 5) = 0 (x – 2) (2 x – 5) = 0 x = 2, 5/2 II. 3y² + 11y + 6 = 0 3y² + 2y + 9 y + 6 = 0 y (3 y + 2) + 3(3 y + 2) = 0 y = -3, -2/3 Hence, x>y
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