Question
If x + 1/x = 4, find x⁵ + 1/x⁵.
Solution
ATQ,
x² + 1/x² = (4)² − 2 = 14 x³ + 1/x³ = (x + 1/x)(x² + 1/x² − 1) = 4(14 − 1) = 52 x⁴ + 1/x⁴ = (x² + 1/x²)² − 2 = 194 x⁵ + 1/x⁵ = (x + 1/x)(x⁴ + 1/x⁴ − x² − 1/x²) = 4(194 − 14) = 720
More Quadratic equation Questions
- I.√(3x-17)+ x=15 II. y+ 135/y=24
- I. x2 + 25x + 154 = 0 II. y2 + 27y + 181 = 0
- I. 2y2 - 37y + 143 = 0 II. 2x2 + 15x – 143 = 0
- I. 22x² - 97x + 105 = 0 II. 35y² - 61y + 24 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: x² - 40x + 300 = 0 Equation 2: y² - 30y + 216 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: 2x² - 8x + 6 = 0 Equation 2: y² - 7y + 10 = 0
- Solve the quadratic equations and determine the relation between x and y: Equation 1: x² - 54x + 704 = 0 Equation 2: y² - 44y + 448 = 0
- Two quadratic equations I and II are given below. Equation I: ax² - 33x + ab = 0 Equation II: cy² - 34y + 2cd = 0 Note: (i) Sum of the values of 'a' an...
- I. 8x² + 2x – 3 = 0 II. 6y² + 11y + 4 = 0
- I. 56x² - 99x + 40 = 0 II. 8y² - 30y + 25 = 0