📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

    One Click Can Change Your Exam Journey—Do It Before It Ends! ⏰

    Question

    I. 5x² + 17x + 6 = 0                       

                        II. 2y² + 11y + 12 = 0 In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer.  
    A X > Y Correct Answer Incorrect Answer
    B X < Y Correct Answer Incorrect Answer
    C X ≥Y Correct Answer Incorrect Answer
    D X ≤ Y Correct Answer Incorrect Answer
    E Relation cannot be established Correct Answer Incorrect Answer

    Solution

    I. 5x² + 17x + 6 = 0 5x² + 15x + 2x + 6 = 0 5x (x + 3) +2(x + 3) = 0  x = − 3, − 2/5  II. 2y² + 11y + 12 = 0 2y² + 8y + 3y + 12 = 0 2y (y + 4) + 3 (y + 4) = 0  y = − 4, − 3/2  Hence, no relation can be established between x and y. Alternate Method: if signs of quadratic equation is +ve and +ve respectively then the roots of equation will be -ve and -ve.    So, roots of first equation = x = -3, -2/5 So, roots of second equation = y = -4, -3/2 After comparing roots of quadratic equation we can conclude that relation cannot be established between x and y.

    Practice Next
    More Quadratic equation Questions

    Relevant for Exams:

    ask-question