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I. 5x² + 17x + 6 = 0 5x² + 15x + 2x + 6 = 0 5x (x + 3) +2(x + 3) = 0 x = − 3, − 2/5 II. 2y² + 11y + 12 = 0 2y² + 8y + 3y + 12 = 0 2y (y + 4) + 3 (y + 4) = 0 y = − 4, − 3/2  Hence, no relation can be established between x and y. Alternate Method: if signs of quadratic equation is +ve and +ve respectively then the roots of equation will be -ve and -ve.  So, roots of first equation = x = -3, -2/5 So, roots of second equation = y = -4, -3/2 After comparing roots of quadratic equation we can conclude that relation cannot be established between x and y.
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