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      Question

      I. 2 x² - 15 + 18 = 0

      II. x²- 3 + 2 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer.
      A If x ≥ y Correct Answer Incorrect Answer
      B If x ≤ y Correct Answer Incorrect Answer
      C If x > y Correct Answer Incorrect Answer
      D If x < y Correct Answer Incorrect Answer
      E If x = y or relationship between x and y cannot be established Correct Answer Incorrect Answer

      Solution

      I. 2 [if gte msEquation 12]> x [if !msEquation]--> [endif]--> x² - 15 x + 18 = 0 (2 x - 3) ( [if gte msEquation 12]>x [if !msEquation]--> [endif]--> x - 6) = 0 [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> [if gte msEquation 12]>x [if !msEquation]--> x = `(3)/(2), 6` [if gte msEquation 12]> 3 2 , 6 [if !msEquation]--> [endif]--> II. y²- 3 y+ 2 = 0 ( [if gte msEquation 12]>y [if !msEquation]--> [endif]--> y – 1) ( [if gte msEquation 12]>y [if !msEquation]--> [endif]--> y – 2) = 0 [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> y [if gte msEquation 12]>y [if !msEquation]--> [endif]--> = 1, 2 Hence, relationship between x [if gte msEquation 12]>x [if !msEquation]--> [endif]--> and y [if gte msEquation 12]>y [if !msEquation]--> [endif]--> cannot be established.

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