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Question

I. 81x - 117radic;x + 40 = 0

II. 81y - 225radic;y + 136 = 0

A if x Correct Answer Incorrect Answer
B if x>y Correct Answer Incorrect Answer
C if x≤y Correct Answer Incorrect Answer
D if x=y or the relationship cannot be established. Correct Answer Incorrect Answer
E if x≥y Correct Answer Incorrect Answer

Solution

I. 81x - 117radic;x + 40 = 0 81x - 72radic;x - 45radic;x + 40 = 0 9radic;x (9radic;x ndash; 8) ndash; 5 (9radic;x ndash; 8)= 0 (9radic;x ndash; 5) (9radic;x ndash; 8) = 0 x = 25/81, 64/81 II. 81y - 225radic;y + 136 = 0 81y - 72radic;y - 153radic;y + 136 = 0 9radic;y (9radic;y ndash; 8) ndash; 17 (9radic;y ndash; 8) = 0 (9radic;y ndash; 8) (9radic;y ndash; 17) = 0 y = 289/81, 64/81 Hence, x le; y.

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