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    Question

    I.  2(x+2)+ 2(-x)=5 II.

     (1/(y+1)+ 1/(y+5))=(1/(y+2)+  1/(y+4)) In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;
    A x < y Correct Answer Incorrect Answer
    B x > y Correct Answer Incorrect Answer
    C x = y or no relationship cannot be established between x and y Correct Answer Incorrect Answer
    D x ≥ y Correct Answer Incorrect Answer
    E x ≤ y Correct Answer Incorrect Answer

    Solution

     2(x+2)+ 2(-x)=5 2x  ×2² +  1/2x - 5=0  Put 2x = a We get 4a+  1/a- 5=0  4a²+1-5a=0  4a²-4a-a+1=0  (4a-1)(a-1)= 0  a=1,1/4  If 2^x=1 x=0  2^x=1/4    If, 2^x=1/2²    x= -2  (1/(y+1)+ 1/(y+5))=(1/(y+2)+  1/(y+4))  (1/(y+1)- 1/(y+4))=(1/(y+2)-  1/(y+5))  (y+4-y-1)/(y+1)(y+4) =  (y+5-y-2)/((y+2)(y+5))  3/(y+1)(y+4) =  3/((y+2)(y+5))  1/(y+1)(y+4) -  1/((y+2)(y+5))=0  ((y+2)(y+5)- (y+1)(y+4))/((y+1)(y+4)(y+2)(y+5))=0  y²+7y+10-(y^2+ 5y+4)=0    y²+7y+10-y²-5y-4=0  2y+6=0  y= -3  Hence, x>y

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