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    Question

    I. (2x-3)3+  1/((2x-3)³)=2  II.  

    4y²+(y+8)^2= 157 In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;
    A x < y Correct Answer Incorrect Answer
    B x > y Correct Answer Incorrect Answer
    C x = y or no relationship cannot be established between x and y Correct Answer Incorrect Answer
    D x ≥ y Correct Answer Incorrect Answer
    E x ≤ y Correct Answer Incorrect Answer

    Solution

    let 2x-3=a  (2x-3)3+  1/((2x-3)³)=2  a³+  1/(a³ )=2  a6+ 1=2a³  a6- 2a³+1=0  (a3- 1)2= 0  a³=1  a=1  2x-3=1  2x=4  x=2  4y²+(y+8)2= 157  4y²+y²+64+16y=157  5y²+16y-93=0  5y2-15y+31y-93=0  5y(y-3)+31(y+3)= 0  5y(y-3)+31(y- 3)= 0 y=3,-31/5  Hence, no relationship cannot be established between x and y.

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