Question
The quadratic equation (p + 1)x 2 -Â 8(p +
1)x + 8(p + 16) = 0 (where p ≠-1) has equal roots. find the value of p.Solution
(p + 1)x2 - 8(p + 1)x + 8(p + 16) = 0, p ≠-1 Since, above equation has equal roots, So discriminant, D = b2 -4ac = 0 Hence {-8(p + 1)}2 - 4 
(p + 1) 8(p + 16) = 0 or 32(p+1) { 2p - (p+16)} = 0 or 32(p+1) (p-14) = 0 So p = -1, 14 as p ≠-1, So p = 14
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