I. x2-2x- √5x+2√5 = 0 II. y2-√3 y- √2 y+ √6 = 0

I. x 2 -2x- √5x+2√5 = 0 x(x-2)- √5 (x-2) = 0 (x-2)( x-√5) = 0 x = 2,√5 II. y 2 -√3 y- √2 y+ √6 = 0 y (y- √3)-√2 (y-√3) = 0 (y- √3)( y- √2 )= 0 y=√3,√2 Hence, x>y

Question

In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;

I. x²-2x- √5x+2√5 = 0

II. y²-√3 y- √2 y+ √6 = 0

A if x = y

B if x > y

C if x < y

D if x ≥ y

E if x ≤ y

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IBPS SO

Question

I. x²-2x- √5x+2√5 = 0

II. y²-√3 y- √2 y+ √6 = 0

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