Question

    I. x2-2x- √5x+2√5 = 0 II.

    y2-√3 y- √2 y+ √6 = 0 In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;
    A if x = y Correct Answer Incorrect Answer
    B if x > y Correct Answer Incorrect Answer
    C if x < y Correct Answer Incorrect Answer
    D if x ≥ y Correct Answer Incorrect Answer
    E if x ≤ y Correct Answer Incorrect Answer

    Solution

    I. x2-2x- √5x+2√5 = 0 x(x-2)- √5 (x-2) = 0 (x-2)( x-√5) = 0 x = 2,√5 II. y2-√3 y- √2 y+ √6 = 0 y (y- √3)-√2 (y-√3) = 0 (y- √3)( y- √2 )= 0 y=√3,√2 Hence, x>y

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