Question
A and B together have to complete a piece of work
consisting of 160 equal units. A can do (x + 2) units of work per day and B can do (x β 2) units per day. They complete the work together in 5 days. In how many days can A alone complete the entire work?Solution
ATQ, Total work = 160 units Combined daily work of A and B = (x + 2) + (x β 2) = 2x units/day They finish in 5 days β Total work = 5 Γ (2x) = 10x So, 10x = 160 x = 16 Aβs speed = x + 2 = 18 units/day Time for A alone = 160 / 18 = 80 / 9 days = 8 8/9 days
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