Question
'B' is 20% more efficient than 'A.' 'A' began working on
a task alone and continued for 8 days, after which 'B' took over and completed the remaining work alone in 5 days. Now, In how many days 'A' would require to complete the entire task if they worked alone.Solution
ATQ, Let the efficiency of ‘A’ = ‘10y’ units/day Then, efficiency of ‘B’ = 10y × 1.2 = ‘12y’ units/day So, total work = (10y × 8) + (12y × 5) = ‘140y’ units So, time taken by ‘A’ to complete the whole work alone = (140y/10y) = 14 days
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