Question
'B' is 20% more efficient than 'A.' 'A' began working on
a task alone and continued for 8 days, after which 'B' took over and completed the remaining work alone in 5 days. Now, In how many days 'A' would require to complete the entire task if they worked alone.Solution
ATQ, Let the efficiency of βAβ = β10yβ units/day Then, efficiency of βBβ = 10y Γ 1.2 = β12yβ units/day So, total work = (10y Γ 8) + (12y Γ 5) = β140yβ units So, time taken by βAβ to complete the whole work alone = (140y/10y) = 14 days
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