Question
'A cyclist travels a certain
distance at a speed of 18 km/h and reaches 3 hours late. If he had cycled at a speed of 27 km/h, he would have reached on time. Find the distance he cycled.'Solution
ATQ, Let the appropriate time taken by the cyclist to travel the distance = t hours. Let the distance travelled by the cyclist = d km. We have: 118(t+3)=d 27t=d Equating both: 18t+54=27t 9t=54 t=6 Now, d=27t=27×6=162 km
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