Question
A coin is tossed. If head occurs, a ball is drawn from a
bag containing 3 red and 4 green balls. If tail occurs, a die is thrown. The probability that the final outcome is a green ball or a prime number is:Solution
Coin toss outcomes: – P(Head) = 1/2 – P(Tail) = 1/2 If head occurs: – Bag contains 3 red and 4 green balls → total = 7 – P(Green | Head) = 4/7 – P(Green ball) = (1/2) × (4/7) = 2/7 If tail occurs: – A die is thrown – Prime outcomes = {2, 3, 5} → 3 favourable out of 6 – P(Prime | Tail) = 3/6 = 1/2 – P(Prime number) = (1/2) × (1/2) = 1/4 Since both cases are mutually exclusive, total probability = 2/7 + 1/4 = (8 + 7)/28 = 15/28
22 15 10 20 33 93.5
...6, 17, 21, 47, ?, 107
The question below is based on the given series I. The series I satisfy a certain pattern, follow the same pattern in series II and answer the question...
171, 173, 183, 213 , ‘?’, 411, 633.
342Â Â Â 252Â Â Â 172Â Â Â 102Â Â Â 42Â Â Â ?
14 20 35 ? 433 2167
...5468, 2734, 1367, 683.5, 341.75, ?
52 25 27 ? 208 1648
...800    544    416    352    ?     304
6Â Â Â Â Â Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â Â Â Â Â Â 24Â Â Â Â Â Â Â Â Â Â Â 218Â Â Â Â Â Â Â Â Â 3486Â Â Â Â Â Â Â 43575
10      �...
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