Question
A man buys two cows for a total of $4,000. He sells one
at a 20% profit and the other at a 20% loss. If the selling prices of both cows are the same, find the cost price of each cows.Solution
Let the cost price of the first cow be x. Then the cost price of the second cow will be (4000 – x) Selling price of the first cow = 120% of x Selling price of the second cow = 80% of (4000 - x) Given that both selling prices are the same: 120% of x = 80% of (4000 - x) 3x = 2(4000-x) 3x = 8000-2x 5x = 8000 x = 1600 4000-x = 4000-1600 = 2400
Identify the alternative which resemble the mirror-image of the given word. SECRETARY
1.
Select the correct mirror image of the given figure when the mirror is placed to the right side of the f igure at ‘MN ’.
Select the correct mirror image of the given figure when the mirror is placed along MN as shown.
Select the correct mirror image of the given figure when the mirror is placed on the right side of the figure.
If 512 C 8 = 64 and 729 C 9 = 81, then 1000 C 10 = ?
Select the correct mirror image of the given figure when the mirror is placed to the right of the figure.
Choose the alternatives which is closely resembles the mirror image of the given combination.
Select the correct mirror image of the given combination when the mirror is placed at ‘XX’ as shown.
Select the correct mirror image of the given combination when the mirror is placed at ‘AB’ as shown.
