Question
A man buys two cows for a total of $4,000. He sells one
at a 20% profit and the other at a 20% loss. If the selling prices of both cows are the same, find the cost price of each cows.Solution
Let the cost price of the first cow be x. Then the cost price of the second cow will be (4000 – x) Selling price of the first cow = 120% of x Selling price of the second cow = 80% of (4000 - x) Given that both selling prices are the same: 120% of x = 80% of (4000 - x) 3x = 2(4000-x) 3x = 8000-2x 5x = 8000 x = 1600 4000-x = 4000-1600 = 2400
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