Question
A can complete a work in 12 days and B can complete the
same work in 18 days. They work together for 4 days, after which A leaves. In how many more days will B alone complete the remaining work?Solution
A's 1-day work = 1/12 B's 1-day work = 1/18 Together 1-day work = 1/12 + 1/18 = 3/36 + 2/36 = 5/36 Work done in 4 days = 20/36 = 5/9 Remaining work = 1 - 5/9 = 4/9 Time taken by B alone = (4/9) ÷ (1/18) = (4/9) × 18 = 8 days Hence, the correct answer is 8 days.
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