Question
A, B, and C can complete a task individually in 45, 35,
and 63 days respectively. They start working together, but A leaves 24 days before the work is completed, and B leaves 10 days after A leaves. How many total days does it take to finish the work?Solution
Let total amount of work = 315 units (LCM of 45, 35 and 63)
Amount of work done by A in one day = 315/45 = 7 units
Amount of work done by B in one day = 315/35 = 9 units
Amount of work done by C in one day = 315/63 = 5 units
Let total time taken to complete the whole work is ‘x’ days
According to question;
5 × x + 9 × (x – 14) + 7 × (x – 24) = 315
Or, 21x = 315 + 168 + 126
Or, 21x = 609
Or, x = 29
The questions below are based on the given Series-I. The series-I satisfies a certain pattern, follow the same pattern in Series-II and answer the ques...
4 5.5 19 .5 98.5 694 6251.5
...42 43 46 ...
203, 223, 198, 218, ?, 213
400 596 452 552 488 524
100 a �...
111 113 117 120 ? 133
85 135 172 ? 215 225
There are 3 series, you have to find value of a, b, c and then establish relation among a,b,c.
19, 25, 45, a, 553, 2767
1560 760 360 160 6...
5 13 36 145 719 4321
84, 61, 80, 57, 76, ?