Question
A, B, and C can complete a task individually in 45, 35,
and 63 days respectively. They start working together, but A leaves 24 days before the work is completed, and B leaves 10 days after A leaves. How many total days does it take to finish the work?Solution
Let total amount of work = 315 units (LCM of 45, 35 and 63)
Amount of work done by A in one day = 315/45 = 7 units
Amount of work done by B in one day = 315/35 = 9 units
Amount of work done by C in one day = 315/63 = 5 units
Let total time taken to complete the whole work is βxβ days
According to question;
5 Γ x + 9 Γ (x β 14) + 7 Γ (x β 24) = 315
Or, 21x = 315 + 168 + 126
Or, 21x = 609
Or, x = 29
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