Question
If O is circumcentre of acute angled triangle ABC, if
∠ OBC = 300 then ∠BAC = ?Solution
∠ OBC = ∠ OCB= 300 as radius are equal. ∠ OBC+ ∠OCB + ∠BOC =180 0 300 + 300 + ∠BOC =180 0 So, ∠BOC = 120 0 Now, ∠ BOC = 2 ∠ BAC So, ∠BAC = 1/2 of ∠BOC = 1/2 of 120 0 = 600
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