Question
If O is circumcentre of acute angled triangle ABC, if ∠ OBC = 300 then ∠BAC = ?
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∠ OBC = ∠ OCB= 300 as radius are equal. ∠ OBC+ ∠ OCB + ∠ BOC =180 0 300 + 300 + ∠ BOC =180 0 So, ∠ BOC = 120 0 Now, ∠ BOC = 2 ∠ BAC So, ∠ BAC = 1/2 of ∠ BOC = 1/2 of 120 0 = 600