Question
If O is circumcentre of acute angled triangle ABC, if
â Â OBC = 300 then â BAC = ?Solution
â  OBC = â  OCB= 300 as radius are equal. â  OBC+ â OCB + â BOC =180 0 300 + 300 + â BOC =180 0 So, â BOC = 120 0 Now, â  BOC = 2 â  BAC So, â BAC = 1/2 of â BOC = 1/2 of 120 0 = 600
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