Question
A completes 1/3 of a task in 4 days, while B finishes
the remaining work in 8 days. If B is 25% less efficient than C, how many days will A, B, and C together take to complete 5/6 of the task?Solution
Time taken by ‘A’ to complete the whole work = 4 × 3 = 12 days
Time taken by ‘B’ to complete the whole work = 8 × (3/2) = 12 days
Time taken by ‘C’ to complete the whole work = 0.75 × 12 = 9 days
Let the total work be 36 units
Efficiency of ‘A’ = 36/12 = 3 units/day
Efficiency of ‘B’ = 36/12 = 3 units/day
Efficiency of ‘C’ = 36/9 = 4 units/day
Required time taken = (5/6) × (36/10) = 3 days
√2401 × (√2116 ÷ 23) × 21 ÷ 3 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
?3 - (77.98 ÷ 6.09 + 10.12)2 + (2.015 - 11.983)2 = 20.01 × (215.98(2/3) - √36.03)
(29.97%) of 9840 + ? + (45.17% of 1240) = (31.955% of 11750)
386.99 + 397.99 + ? - 232.02 = 35.02 × 31.99
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question?
(6981.45% of 58.67 ÷ 17.78 + 1410.52) ÷ 27....What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
