Question
A completes 1/3 of a task in 4 days, while B finishes
the remaining work in 8 days. If B is 25% less efficient than C, how many days will A, B, and C together take to complete 5/6 of the task?Solution
Time taken by ‘A’ to complete the whole work = 4 × 3 = 12 days
Time taken by ‘B’ to complete the whole work = 8 × (3/2) = 12 days
Time taken by ‘C’ to complete the whole work = 0.75 × 12 = 9 days
Let the total work be 36 units
Efficiency of ‘A’ = 36/12 = 3 units/day
Efficiency of ‘B’ = 36/12 = 3 units/day
Efficiency of ‘C’ = 36/9 = 4 units/day
Required time taken = (5/6) × (36/10) = 3 days
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