Question
A completes 1/3 of a task in 4 days, while B finishes
the remaining work in 8 days. If B is 25% less efficient than C, how many days will A, B, and C together take to complete 5/6 of the task?Solution
Time taken by βAβ to complete the whole work = 4 Γ 3 = 12 days
Time taken by βBβ to complete the whole work = 8 Γ (3/2) = 12 days
Time taken by βCβ to complete the whole work = 0.75 Γ 12 = 9 days
Let the total work be 36 units
Efficiency of βAβ = 36/12 = 3 units/day
Efficiency of βBβ = 36/12 = 3 units/day
Efficiency of βCβ = 36/9 = 4 units/day
Required time taken = (5/6) Γ (36/10) = 3 days
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