Question
A and B can jointly finish a task in 42 days, while B
and C together take 35 days to finish the same task. If B can finish the task alone in 105 days, how long would it take for A and C to complete the task together?Solution
Let total work = 210 units (LCM of 42, 35 and105) Amount of work done by A and B together in one day = 210/42 = 5 units Amount of work done by B and C together in one day = 210/35 = 6 units Amount of work done by B in one day = 210/105 = 2 units Amount of work done by A in one day = 5 – 2 = 3 units Amount of work done by C in one day = 6 – 2 = 4 units Desired time = 210/(4 + 3) = 30 days
More Time and work Questions
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
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