Question
A and B can jointly finish a task in 42 days, while B
and C together take 35 days to finish the same task. If B can finish the task alone in 105 days, how long would it take for A and C to complete the task together?Solution
Let total work = 210 units (LCM of 42, 35 and105) Amount of work done by A and B together in one day = 210/42 = 5 units Amount of work done by B and C together in one day = 210/35 = 6 units Amount of work done by B in one day = 210/105 = 2 units Amount of work done by A in one day = 5 – 2 = 3 units Amount of work done by C in one day = 6 – 2 = 4 units Desired time = 210/(4 + 3) = 30 days
Statements: Z % Y; X # W; U % V; W & V; Y @ X
Conclusions:Â Â Â Â Â
I. U @ X Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â ...
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Conclusions:
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