Question
A can do a piece of work in 28 days, while B can do the
same piece of work in 42 days. They begin working together and 6 days before completion of work, A leaves. Find the total number of days taken to complete the work.Solution
Suppose the work finished in x days. A' s one day work is 1/28 day B's one day work is 1/42 day According to the question, Let the total work was done in x days then, A works for (x - 6)days Then, (x - 6)/28 + x/42 = 1 3x – 18 + 2x = 84 5x = 102 x = 102/5 days. Alternate Method: A B 28 42 let total work = LCM of 28 & 42 = 84 units So Eff : 3 : 2 So in last 6 days B worked alone so his work in last 6 days = 2`xx` 6 = 12 units So remaining work = 84-12 = 72 units Hence A & B will do it in = 72/5days Hence total days = 72/5 +6 = 102/5 days
14    36    80    168    ?     696
9    14    38    129    ?   2705   16260
...324Â Â Â Â Â Â Â Â 972Â Â Â Â Â Â Â Â 486Â Â Â Â Â Â Â Â 1458Â Â Â Â Â Â 729Â Â Â Â Â Â Â Â ?
...168, 178, ?, 273, 400, 618, 963
98, 134, 198, ?, 442, 638
200 ? 96 38.4 7.68 0
64, 79, 109, 169, 289, ?
- What will come in place of (?), in the given number series.
2, 5, 10, 17, ?, 37 What will come in place of the question mark (?) in the following series?
80, 200, 400, 600, ?, 300
What will come in place of the question mark (?) in the following series?
1458, ?, 162, 54, 18, 6
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