Question
3 men and 4 boys can together complete a work in 10
days. 4 men and 2 boys can together complete the same work in 8 days. Find the time taken by 8 boys together to complete the entire work.Solution
Let the efficiency of a boy be 'B' units/day and the efficiency of a man be 'M' units/day we have, (3M + 4B) X 10 = (4M + 2B) X 8 Or, 30M + 40B = 32M + 16B Or, 24B = 2M So, B:M = 1:12 So, let B = '1a' and M = '12a' Total work = (3 X 12a + 4 X 1a) X 10 = '400a' units So, time taken by 8 boys together to complete the work = 400a ÷ (8 X 1a) = 50 days
State true or false
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