Question
A and B can complete a task together in 24 days, while B alone takes 48 days to finish it. A began working alone and left after βxβ days, after which B completed the remaining work in 36 days. Determine the percentage of the total work completed by
A.
Solution
Let total amount of work be 48 units
Efficiency of (A + B) = 48/24 = 2 units/day
Efficiency of βBβ = 48/48 = 1 unit/day
Amount of work done by βBβ = 36 Γ 1 = 36 units
Percentage of work done by βAβ = {(48 β 36)/48} Γ 100 = 25%
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