Question
βAβ is 50% less productive compared to βBβ, who
is 20% more productive than βCβ. Together, they can finish a task in 36 days. After βBβ and βCβ have worked on the task for 24 days, they stop. How long will it take for βAβ to finish the remaining work alone?Solution
Let efficiency of βBβ is βxβ units per day
Efficiency of βAβ = 0.50 Γ x = 0.5x units per day
Efficiency of βCβ = x/1.20 = 0.833x units per day
Total amount of work = (x + 0.5x + 0.833x) Γ 36 = 84x units
Amount of work completed by βBβ and βCβ in 24 days = (x + 0.833x) Γ 24 = 43.99x β 44x units
Remaining work = 84x β 44x = 40x units
Desired time = 40x / 0.5x = 80 days
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