Question
‘A’ is 50% less productive compared to ‘B’, who is 20% more productive than ‘C’. Together, they can finish a task in 36 days. After ‘B’ and ‘C’ have worked on the task for 24 days, they stop. How long will it take for ‘A’ to finish the remaining work alone?
Solution
Let efficiency of ‘B’ is ‘x’ units per day
Efficiency of ‘A’ = 0.50 × x = 0.5x units per day
Efficiency of ‘C’ = x/1.20 = 0.833x units per day
Total amount of work = (x + 0.5x + 0.833x) × 36 = 84x units
Amount of work completed by ‘B’ and ‘C’ in 24 days = (x + 0.833x) × 24 = 43.99x ≈ 44x units
Remaining work = 84x – 44x = 40x units
Desired time = 40x / 0.5x = 80 days
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