Question
A man, a woman and a boy can do a work in 3, 2, 6 days
respectively. How many children were required with 1 man and 1 woman to complete the same work in (1 )/(2 ) day?Solution
Work done by a man in (1)/(2) days = (1)/(6 ) part Work done by a woman in (1)/(2) days = (1)/(4) part Work done by a boy in (1)/(2) days = (1)/(12) part Let one man and one woman together can do a piece of work in (1)/(2) days = No. of x children required According to the question, => (1)/(6) + (1)/(4) + (x)/(12) = 1 => (2 + 3 + x)/(12) = 1 => 5 + x = 12 => x = 12 – 5 = 7 Hence, 7 boys will be required.
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