Question
Karan, Arjun and Krunal alone can complete a work in 35,
70 and 60 days respectively. All of them started working together but after 3 days from start Karan left the job and after 5 more days Arjun also left the job. So for how many days did Krunal work?Solution
Let the total work = 420 units (LCM of 35, 70 and 60) Amount of work done by Karan alone in one day = 420/35 = 12 units Amount of work done by Arjun alone in one day = 420/70 = 6 units Amount of work done by Krunal alone in one day = 420/60 = 7 units Amount of work done by Karan, Arjun and Krunal together in 3 days = 3 × (12 + 6 + 7) = 75 units Amount of work done by Arjun and Krunal together in 5 days = 5 × (6 + 7) = 65 units Remaining work = 420 – 75 – 65 = 280 units So, the time taken by Krunal alone to complete 280 units work = 280/7 = 40 days So, Krunal worked for 40 + 5 + 3 = 48 days
6000 3002 1503 ? 378.75 191.375 97.6875
...1, 27, ?, 343, 729, 1331
(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?
51 53 109 332 ? 6686
...9 4.5 4.5 9 36 ?
5 16 ? 66 119 200
...1 1 8 4 27 9 ?
...What will be the next number in the series?
2, 7, 23, 70, ?
There are three series given below which are following with the same pattern.
Series I: 1, 12, 38, 193, 1355
Series II: 6, B, C, D, E
...Direction: Which of the following will replace ‘?’ in the given question?
5, 18, ‘?’, 126, 296, 586, 1044