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    Question

    ‘A’ can complete a job in 36 days. ‘B’ takes 3

    times as long as ‘A’ to finish the same job. If both work together, how much of the work will they finish in 18 days?
    A 1/3 Correct Answer Incorrect Answer
    B 2/3 Correct Answer Incorrect Answer
    C 5/3 Correct Answer Incorrect Answer
    D 3/2 Correct Answer Incorrect Answer

    Solution

    ATQ,

    Time taken by ‘B’ to complete the total work = 36 × 3 = 108 days

    Let total work be 108 units (LCM of 36 and 108)

    Efficiency of ‘A’ = 108 / 36 = 3 units/day

    Efficiency of ‘B’ = 108 / 108 = 1 unit/day

    Work done in 18 days = (3 + 1) × 18 = 72 units

    So, together they complete = 72 / 108 = 2/3 of the total work

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