Question
‘A’ can complete a job in 36 days. ‘B’ takes 3
times as long as ‘A’ to finish the same job. If both work together, how much of the work will they finish in 18 days?Solution
ATQ,
Time taken by ‘B’ to complete the total work = 36 × 3 = 108 days
Let total work be 108 units (LCM of 36 and 108)
Efficiency of ‘A’ = 108 / 36 = 3 units/day
Efficiency of ‘B’ = 108 / 108 = 1 unit/day
Work done in 18 days = (3 + 1) × 18 = 72 units
So, together they complete = 72 / 108 = 2/3 of the total work
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