Question
A can finish a piece of work in 12 days, B in 15 days. They work together for 4 days, then A leaves and C joins
B. C is 25% more efficient than
B. In how many total days will the work be finished?
Solution
A = 1/12, B = 1/15 per day. In 4 days: Work done = 4 × (1/12 + 1/15) = 4 × (9/60) = 0.6. Remaining = 0.4. C = 1.25 × (1/15) = 1/12. B + C = 1/15 + 1/12 = 7/60. Time for remaining = 0.4 ÷ (7/60) = 24/7 = 8/3 days. Total = 4 + 8/3 = 20/3 days.
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