Question
In the question, two equations I and II are given. You
have to solve both the equations to establish the correct relation between x and y and choose the correct option. I. (x + 2)Β² = 15x β 26 II. (y β 6)Β² = 6 β ySolution
ATQ,
(x + 2) Β² = 15x β 26
xΒ² + 4x + 4 = 15x β 26
xΒ² β 11x + 30 = 0
xΒ² β 5x β 6x + 30 = 0
x(x β 5) β 6(x β 5) = 0
(x β 5)(x β 6) = 0
x = 5, 6
From II:
(y β 6) Β² = 6 β y
yΒ² β 12y + 36 = 6 β y
yΒ² β 11y + 30 = 0
yΒ² β 5y β 6y + 30 = 0
y(y β 5) β 6(y β 5) = 0
(y β 5)(y β 6) = 0
y = 5, 6
So, the relationship cannot be established.
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