Question
6 men and 6 women can do some work in 3 days. If each
man is 200% more efficient than a woman, then find the time taken by 12 men to finish the same work together.Solution
Let the efficiency of each woman be 'x' units/day. So, efficiency of each man = 3x units/day So, total work = 3 × {(6 × 3x) + (6 × x)} = '72x' units So, required time = 72x ÷ (12 × 3x) = 2 days
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