Question
A can complete a work in 15 days. B takes 5 days less
than A to complete the same work. In how many days can both of them together complete 60% of the work together?Solution
Time taken by B to complete the work = 15 – 5 = 10 days Let the total work = 30 units Efficiency of A = 30/15 = 2 units/day Efficiency of B = 30/10 = 3 units/day Required time taken = 0.60 x 30/(2+3) = 3.6 days
3456 1728 2592 6485 22680 102060
...299, 302, 308, 317, ?, 344
2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 10Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â ...
230, 34.5, ‘?’, 0.77625
If 10 9 38 x 5428
Then, 2x² + 1 = ?
...There are two series I and II. Logic in both the series are different.
Series l: 3, 12, 28, 53, 89, .
Series II: 259, 270, 283, 300, 319.<...
12, 6, 6, 9, 18, ?
If   314     306      x      269       394    178    1480
Then, 1/3 x + 2x - x = ?
...5     16     ?      66     119      200
...9999 6666 ? 2962.66 1975.11 1316. 74
...
