Question
A work can be completed by ‘A’ and ‘B’, alone in
15 days and 10 days, respectively. Find the number of days taken by ‘C’ to complete the same work alone if ‘A’, ‘B’ and ‘C’ together can complete the whole work in 5 days.Solution
Let total work = 30 units (LCM of 15 and 10) Efficiency of ‘A’ = (30/15) = 2 units/day Efficiency of ‘B’ = (30/10) = 3 units/day Combined efficiency of ‘A’, ‘B’ and ‘C’ = (30/5) = 6 units/day Efficiency of ‘C’ = 6 – (2 + 3) = 1 units/day Required time taken = (30/1) = 30 days
If 152,   242,    x ,  332,   404,    314,
then find the value of (2x – 1)?
...A factory produces two types of gadgets: Type A and Type B. In a day, it produces 300 Type A gadgets and 400 Type B gadgets. If the production cost of T...
Find the missing term.
D – 4, F – 6, H – 8, J – 10, ?, ?
1335Â Â Â Â Â Â 737Â Â Â Â Â Â Â Â 355Â Â Â Â Â Â Â Â 141Â Â Â Â Â Â Â Â 47Â Â Â Â Â Â Â Â Â Â ?
...32, 128, ?, 2048, 8192, 32768
17                          26                          37                   �...
0.5 1.5 5 ? 76 385
...Identify the logic of the below given series and given answer.
Series I :: 81, 89, 116, 241, (A), 1915
Series II :: (B), 204, 208, 4...
2, A, 9, B, 6, C, 13, D, ?
Choose the correct alternative
21: 3 ∷ 574: ?
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