Question
Neha is five times as efficient as Riya and three times
as efficient as Siya. If Riya takes 20 days to finish some work, then find the time taken by Neha and Siya to do the same work together.Solution
Since, Neha is five times as efficient as Riya, she will take one-fifth the time taken by Riya to finish the work. So, time taken by Neha to do the work = 20 ÷ 5 = 4 days And, Neha is three times as efficient as Siya, so Siya will take three times the time taken by Neha. So, time taken by Siya to do the work = 3 × 4 = 12 days Let the total work be '12x' units. So, efficiency of Neha = 12x ÷ 4 = '3x' units/day And, efficiency of Siya = 12x ÷ 12 = 'x' units/day So, required time = 12x ÷ (3x + x) = 3 days Hence, option b.
Statements: P # B, Q $ B, B @ J, J % F
Conclusions: Â Â Â Â Â I. F # BÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. F @ BÂ Â Â Â Â Â Â Â Â Â Â Â Â Â ...
Statement:
B = E ≥ F ≥ M < J < V ≥ R; M > A
Conclusion:
I) A ≥ R
II) B > A
Statements:
C © S * R, U % R $ Z
Conclusions:
I. Z $ C
II. U % S
III. U © C
Statements:Â
R ≤ A ≤ B > C = X < J < K = L
Conclusions:      I. R ≤ B                 II. L > C   ...
Statement: S > P, P ≥ U, U > V, V ≤ N
Conclusion: I. N ≥ U II. S < N
In the question, assuming the given statements to be true, find which of the following conclusion(s) among the three conclusions is/are true and then g...
Statements:          M%G,   G@I,   I$F,    F&O
Conclusions: Â Â Â Â Â Â Â Â Â
 I. I$M  Â
II. I$OÂ Â Â Â <...
16. Statements:
J ≥ F = P; F > S ≥ A; S ≥ B < C
Conclusions:
I. C > A
II. B < J
In the question, assuming the given statements to be true, find which of the conclusion (s) among given two conclusions is /are definitely true and the...
Statements: D = E ≥ M > H = L, H ≤ F < G ≤ J < I
Conclusions:
I. I > L
II. D ≥ F
III. G < E
