Question
A can do a work in 15 days, B in 20 days. They start
together, but A leaves after 4 days. In how many days is the work completed?Solution
ATQ, (A+B) rate = 1/15 + 1/20 = (4+3)/60 = 7/60 Work in 4 days = 4×7/60 = 28/60 = 7/15 Remaining = 1 − 7/15 = 8/15 B’s rate = 1/20 Time for remaining = (8/15)/(1/20) = (8/15)×20 = 160/15 = 10 2/3 days Total time = 4 + 10 2/3 = 14 2/3 days
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