Question
Tanu can complete a task in 'A' days on her own, while
together with Manu, they can complete the same task in (A - 6) days. Manu, working alone, can finish the task in 72 days. What would be the time taken by Tanu to finish the task if she works with 33(1/3)% more efficiency than usual?Solution
Work done by Tanu in One day = (1/A) units Work done by Tanu and Manu together in one day = [1/(A - 6) ] units Work done by Manu in one day = (1/72) units ATQ, (1/A) + (1/72) = [1/(A - 6) ] Or, (1/72) = {1/(A - 6) } - (1/A) Or, A X (A - 6) = 72 X 6 Or, A2Â - 6A = 432 Or, A2Â - 6A = 432 Or, A2Â - 6A - 432 = 0 Or, A2Â - 24A + 18A - 432 = 0 Or, A(A - 24) + 18(A - 24) = 0 Or, (A - 24) (A + 18) = 0 So, 'A' = 24 or -18 But since time taken cannot be negative, so 'A' = 24 So, time taken by Tanu to complete the work = 'A' days = 24 days Therefore, required time by Tanu with increased efficiency = 24 x (3/4) = 18 daysÂ
The oxidation of one molecule of NADH in mitochondria results in formation of
Most critical stage of irrigation in wheat crop is:
Which stage does adulteration take place in ?
Physical condition of soil resulted due to tillage is
Match List I with list II
Rotation involving Stylosanthus hamata & Sorghum is an example of
Which of the three geographic races of rice has tall stature, weak stem, droopy leaves, low productivity and irresponsive to high inputs?
Which of the following is not a bottom up technique for the synthesis of nanoparticles?
Cultivation of crops in areas receiving annual rainfall more than750 mm but less than 1150 mm is known as
Total soluble solids are measured by: