Question
'M' alone finishes a project in 30 days. 'M' and 'N'
together can complete the same project in 16(2/3) days. How many days would 'N' need to do the project alone?Solution
ATQ,
Let 16(2/3) = 50/3 Let the total work be 150 units (LCM of 30 and 50/3) Efficiency of M = 150 á 30 = 5 units/day Combined efficiency of M and N = 150 á (50/3) = 9 units/day So, efficiency of N = 9 - 5 = 4 units/day Therefore, time taken by N = 150 á 4 = 37.5 days
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