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Let the efficiency of 'B' be '5x' units/day
So, efficiency of 'A' = 5x X 1.8 = '9x' units/day
So, total work = 10 X (5x + 9x) = '140x' units
So, combined efficiency of 'B' and 'C' = 140x ÷ 7 = '20x' units/day
So, efficiency of 'C' = 20x - 5x = '15x' units/day
So, required ratio = 9x:15x = 3:5
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