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      Question

      β€˜A’ alone can complete a work in 12 days. β€˜B’

      alone can complete the same work in 20 days. If β€˜A’ and β€˜B’ work together for 6 days, then the remaining work can be completed by β€˜A’ alone in how many days?
      A 3.4 days Correct Answer Incorrect Answer
      B 4.4 days Correct Answer Incorrect Answer
      C 3.75 days Correct Answer Incorrect Answer
      D 2.4 days Correct Answer Incorrect Answer

      Solution

      Let the total amount of work = 60 units {LCM of 12 and 20} Then, efficiency of β€˜A’ = 60/12 = 5 units/day Efficiency of β€˜B’ = 60/20 = 3 units/day Combined efficiency of β€˜A’ and β€˜B’ = 5 + 3 = 8 units/day Work completed by β€˜A’ and β€˜B’ together in 6 days = 6 Γ— 8 = 48 units Remaining work = 60 – 48 = 12 units Time taken by β€˜A’ alone to complete the remaining work = 12/5 = 2.4 days

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