Question
‘A’ alone can complete a work in 12 days. ‘B’
alone can complete the same work in 20 days. If ‘A’ and ‘B’ work together for 6 days, then the remaining work can be completed by ‘A’ alone in how many days?Solution
Let the total amount of work = 60 units {LCM of 12 and 20} Then, efficiency of ‘A’ = 60/12 = 5 units/day Efficiency of ‘B’ = 60/20 = 3 units/day Combined efficiency of ‘A’ and ‘B’ = 5 + 3 = 8 units/day Work completed by ‘A’ and ‘B’ together in 6 days = 6 × 8 = 48 units Remaining work = 60 – 48 = 12 units Time taken by ‘A’ alone to complete the remaining work = 12/5 = 2.4 days
25% of 240 + √? = (2/3) × 120
7(1/5) – 3(1/4) + 8(3/4) = ?
(3984 ÷ 24) x (5862 ÷ 40) = ?
(18 × 9 ÷ 6) × 3 = ?
- What will come in the place of question mark (?) in the given expression?
1500 × 60% of 25% = ? 2
In the question, two Quantities I and II are given. You have to solve both the Quantity to establish the correct relation between Quantity-I and Quantit...
? = 60% of 2500 + 85% of 2000 – 5³
What will come in the place of question mark (?) in the given expression?
(55 × 8 + 28) × 10 = ?
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