Question
‘A’ alone can complete a work in 20 days. ‘B’
alone can complete the same work in 25 days. If ‘A’ and ‘B’ work together for 7 days, then the remaining work can be completed by ‘A’ alone in how many days?Solution
Let the total amount of work = 100 units {LCM of 20 and 25} Then, efficiency of ‘A’ = 100/20 = 5 units/day Efficiency of ‘B’ = 100/25 = 4 units/day Combined efficiency of ‘A’ and ‘B’ = 5 + 4 = 9 units/day Work completed by ‘A’ and ‘B’ together in 7 days = 7 × 9 = 63 units Remaining work = 100 – 63 = 37 units Time taken by ‘A’ alone to complete the remaining work = 37/5 = 7.4 days
6000 3002 1503 ? 378.75 191.375 97.6875
...1, 27, ?, 343, 729, 1331
(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?
51 53 109 332 ? 6686
...9 4.5 4.5 9 36 ?
5 16 ? 66 119 200
...1 1 8 4 27 9 ?
...What will be the next number in the series?
2, 7, 23, 70, ?
There are three series given below which are following with the same pattern.
Series I: 1, 12, 38, 193, 1355
Series II: 6, B, C, D, E
...Direction: Which of the following will replace ‘?’ in the given question?
5, 18, ‘?’, 126, 296, 586, 1044
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