Question
A alone can do a piece work in 15 days and the time
taken by A alone is 50% more than the time taken by B. They started work together alternatively starting from A. Find in how many days, they both can complete the work.Solution
A = 15 days B = 15 x (100/150) = 10 days Let the total work be 30 units. Efficiency of A = 2 units Efficiency of B = 3 units Working alternatively starting from A = [30/(2 + 3)] x 2 = 12 days
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