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      Question

      A alone can do a piece work in 15 days and the time

      taken by A alone is 50% more than the time taken by B. They started work together alternatively starting from A. Find in how many days, they both can complete the work.
      A 6 days Correct Answer Incorrect Answer
      B 10 days Correct Answer Incorrect Answer
      C 12 days Correct Answer Incorrect Answer
      D 15 days Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      A = 15 days B = 15 x (100/150) = 10 days Let the total work be 30 units. Efficiency of A = 2 units Efficiency of B = 3 units Working alternatively starting from A = [30/(2 + 3)] x 2 = 12 days

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