A and B together can do a work in 8 days. If A can alone do the same work in 12 days, then in how many days B alone will do the same work?
Total work = Number of days×1 day’s work (efficiency) Total work = LCM (8, 12) = 24 unit 1 day’s work of (A+B) = 24/8 = 3 unit 1 day’s work of A = 24/12 = 2 unit 1 day’s work of B = 3 - 2 = 1 unit Now, Time taken by B to completed the work = 24/1 = 24 days
(6.013 – 20.04) = ? + 9.98% of 5399.98
132 × 3 ÷ 11 + 67 − ? = 64 ÷ 8 × 2
{(522 – 482 ) ÷ (27 + 73)} × 35 = ?% of 17
567-4824 ÷ 134 =? × 9
(0.125)³÷ (0.25)² x (0.5)² = (0.5)?-3
(7/4×18/21)+ (51/7× 28/17) + (25/2 × 48/10) =?
(√ 121 x 41) + (3√343 x √289 ) = ? x 19
12(3/5) + 4(1/5) × 3(2/3) =?
[∛(91125/19683 )- ∛(3375/5832 ) ] × ∛(512/9261) = ? - √(484/3969)
5760 ÷ 45 × 15 = ?