Question
I. 2x² - 7x + 3 = 0 II. 8y² - 14y + 5 =
0Solution
I. 2x² - 7 x + 3 = 0 2x² - 6 x - x + 3 = 0 2 x (x – 3) – 1(x – 3) = 0 (2 x – 1) (x – 3) = 0 x = 3, 1/2 II. 8 y² - 14 y + 5 = 0 8 y² - 4 y - 10 y + 5 = 0 4 y(2 y – 1) – 5 (2 y – 1) = 0 y = 1/2, 5/4 Hence, relationship cannot be established between x and y.
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